If we want to evaluate the integral +18 TE dx √x + 64 we use the trigonometric substitution - and dx = do and therefore
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If we want to evaluate the integral +18 TE dx √x + 64 we use the trigonometric substitution - and dx = do and therefore
If we want to evaluate the integral +18 TE dx √x + 64 we use the trigonometric substitution - and dx = do and therefore the integral becomes, in terms of 0. T- 1- de + The antiderivative in terms of 0 is (do not forget the absolute value) 1 = Finally, when we substitute back to the variable , the antiderivative becomes I Use C for the constant of integration
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