10 16 Loss Power In Copper Walls Of A Fabry Perot Resonator Consider A Fabry Perot Resonator In Fig 10 3 With A St 1 (23.58 KiB) Viewed 42 times
10 16 Loss Power In Copper Walls Of A Fabry Perot Resonator Consider A Fabry Perot Resonator In Fig 10 3 With A St 2 (53.93 KiB) Viewed 42 times
10 16 Loss Power In Copper Walls Of A Fabry Perot Resonator Consider A Fabry Perot Resonator In Fig 10 3 With A St 3 (13.78 KiB) Viewed 42 times
10 16 Loss Power In Copper Walls Of A Fabry Perot Resonator Consider A Fabry Perot Resonator In Fig 10 3 With A St 4 (7.34 KiB) Viewed 42 times
10.16.Loss power in copper walls of a Fabry-Perot resonator. Consider a Fabry-Perot resonator, in Fig. = 10.3, with a standing plane electromagnetic wave given by Eqs. (10.9), where Eo 100 V/m, 6 = xx 10² rad/m, and x 10¹0 rad/s. In addition, let the length of the resonator be a = 3 cm, and let its walls be made of copper (o= 58 MS/m and u-uo) and its dielectric be nonmagnetic. Under these circumstances, compute the time-average power of Joule's losses in the resonator per S = 1 cm² area of its surface (viewed across both walls).
E, μ PEC a=mλ/2 Erot Htot Etot oooood multiple reflections no propagation Z z=-m² z=0 Figure 10.3 Fabry-Perot resonator, obtained by metalizing one of the planes defined by Eq. (10.10), for m = 0, in the field of a standing uniform plane wave in Figs. 10.1 and 10.2.
E tot (t) = 2√2 E io sin 8 z sin w t and
and H tot (t) = 2√/20 COS 8 w tŷ, COS W (10.9)
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