Each step in the following process has a yield of 80.0%. CH+4CLCCI, + 4 HCI CCI +2HF- . CCI₂F₂ + 2HCI The CCI, formed in

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Each step in the following process has a yield of 80.0%. CH+4CLCCI, + 4 HCI CCI +2HF- . CCI₂F₂ + 2HCI The CCI, formed in

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Each Step In The Following Process Has A Yield Of 80 0 Ch 4clcci 4 Hci Cci 2hf Cci F 2hci The Cci Formed In 1
Each Step In The Following Process Has A Yield Of 80 0 Ch 4clcci 4 Hci Cci 2hf Cci F 2hci The Cci Formed In 1 (18.7 KiB) Viewed 30 times
Each step in the following process has a yield of 80.0%. CH+4CLCCI, + 4 HCI CCI +2HF- . CCI₂F₂ + 2HCI The CCI, formed in the first step is used as a reactant in the second step. If 7.50 mol CH₂ reacts, what is the total amount of HCI produced? Assume that Cl, and HF are present in excess. moles HCI: mol
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