Extra Credit Worth 4 Points During The Kinetic Study Of The Reaction 2a Bc D Following Results Were Obtained Run 1 (33.59 KiB) Viewed 24 times
Also, if possible, can you explain in words how/why this following answer's overall reaction is what it is (in part C)? I understand how to get what i got on the left. but i dont understand the overall reaction on the right side!
thank you!
Extra Credit Worth 4 Points During The Kinetic Study Of The Reaction 2a Bc D Following Results Were Obtained Run 2 (35.16 KiB) Viewed 24 times
Extra-Credit (worth 4 points) During the kinetic study of the reaction. 2A+ BC+ D, following results were obtained: Run A/mol I. B/mol L Initial rate of formation of D in mol L s 1 6.0 × 10³ 7.2x 10- 2.88 x 10-¹ 2.40 10-¹ II III IV 0.1 0.3 0.3 0.4 If the general rate law is written. rates ratey Find x, y and k (show all working for full credit) = 0.1 0.2 0.4 0.1 rate, [A] " to [0.1]m [0.19 6.0×10-3 k[A] [0.47m [0.1 2.40*10-3 rate 4 Rate-k [A] (don't forget the units) rate, = £[A] overall 0.0x 10-3 molt¹51 = t3m [0.2]n -7.2×10² [03] [04] 2.88-101 10 5²1 = k [2] = ¹ = 0.35 ª mold. [0.1]' [0.1]' log (0.5)n = 109 (0.25) n = log(0.25) 10g (0.50) n=2 mol 2+ = |M= 0.25 [4] = 10g (0.25) m = log(0.25) m=1 7
21. For the following two-step reaction mechanism, 24₂ 0,(8) 0₂(g) +0 fast O₂(g) + 0(g) 20,(g) slow (a) write out the overall reaction (2 points) 03 (g) + 0 (g) → 20₂ (g) (b) what is the reactive intermediate? (1 points) Og) [what first appears as product then reactant] (c) is the first step or the second step rate determining? (1 point) Secund Cit's the slowest) (c) What is the rate law for this reaction in terms of [O] and [0₂] (6 points) rate= [03] - k-₁ to₂][0] = 0 rate overall rate overall ratez k₂ [03][0] 1 [03] = -1 [0₂][0] k [03] ka [0₂] = [0] f₁ [03] [03] -12-1 [0₂] k₂ k₂ [03]2 ky [0₂]
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