question. Red: MnO4 + 8 H* +5 e→Mn²+ 4 H₂O V compounds.....asking about which is best oxidizing agent and which is best reducing agent Ox agent-stuff is reduced---need high ox # Red agent-stuff oxidized-low ox # [VO(H₂O)]2+ VO²+ solve for V ox #
TICONDEROGAⓇ Oxidation States of Manganese Initial color of Test Tube 1: Colorless (H₂0) Initial color of Test Tube 2: purple (MnO4) Data Table 1: initial color of the solution. pH (basic, neutral, or acidic). final color of the solution color of the precipitate, if any Use the table on page 1 of the lab manual to identify the product in each tube Test Tube Test Tube Test Tube #4 #5 #3 Data Table 21 purple purple people basic neutral acidic (you can check your work for the last row by answering the multiple choice questions in the PostLab-if you get them wrong, try again, it's important that you have these correct for later steps in the lab) Mn initial oxidation state. (you start with MnO4 in all solutions) Mn final oxidation state number of electrons gained by Mn purple purple purple green black Pink Initial and final oxidation states of Mn (use the information above and the Table on page 1 of the manual) Test Tube Test Tube Test Tube # 3 #4 #5 +7 +6 +7 +4 +7 +2
For Tube 5 you'll be given the oxidation reaction and asked to provide the overall balanced equation the reduction reaction is not given. If you've done your work in Table 1 and 2 above, you know what the reduction product is in Tube 5. The reactant is the same in all of the tubes (MnO4) so all you'll have to do is complete the mass and charge balance for this reaction in acidic solution to give you a correctly balanced reduction reaction along with the oxidation half- reaction. Then proceed with completing the overall reaction. You are required to upload this data sheet to show your work for this For Tube 5 you'll be given the oxidation reaction and asked to provide the overall balanced equation the reduction react
-
- Site Admin
- Posts: 899603
- Joined: Mon Aug 02, 2021 8:13 am