50 UNIT 2 Motion, Force, Energy Two-Dimensional Coordinate System: (-3,1) Ax = -3 -2 =t 3 2 V= -1 -2 ↑ 0 -3- 1 (2,3) 2 3

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50 UNIT 2 Motion, Force, Energy Two-Dimensional Coordinate System: (-3,1) Ax = -3 -2 =t 3 2 V= -1 -2 ↑ 0 -3- 1 (2,3) 2 3

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50 Unit 2 Motion Force Energy Two Dimensional Coordinate System 3 1 Ax 3 2 T 3 2 V 1 2 0 3 1 2 3 2 3 1
50 Unit 2 Motion Force Energy Two Dimensional Coordinate System 3 1 Ax 3 2 T 3 2 V 1 2 0 3 1 2 3 2 3 1 (79.71 KiB) Viewed 38 times
50 UNIT 2 Motion, Force, Energy Two-Dimensional Coordinate System: (-3,1) Ax = -3 -2 =t 3 2 V= -1 -2 ↑ 0 -3- 1 (2,3) 2 3 We would need to be given coordinates for P₁ (x₁, y₁) and P₂ (x₂, y₂). Question: What is the displacement for two points: P₁ = (2, 3) and P₂ = (5, 9)? (3,-2) X Δy = The total displacement from P, to P, is given by Pythagorean theorem: Total displacement = √ √4x²+Ay² PROBLEM: Find the total displacement for the two points given above: . Total displacement Total time Now, to discuss movement, if we moved the total displacement given directly above in one hour, the speed would be given by that displacement divided by the 1 hour: Pub Question: Find the velocity from knowing the total displacement above and the time given to move that displacement, 1 hour: or Velocity=
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