You did not answer. (1 point) This problem demonstrates Edfinity questions where the answer is a list of numbers or an i

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You did not answer. (1 point) This problem demonstrates Edfinity questions where the answer is a list of numbers or an i

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You Did Not Answer 1 Point This Problem Demonstrates Edfinity Questions Where The Answer Is A List Of Numbers Or An I 1
You Did Not Answer 1 Point This Problem Demonstrates Edfinity Questions Where The Answer Is A List Of Numbers Or An I 1 (80.22 KiB) Viewed 37 times
You did not answer. (1 point) This problem demonstrates Edfinity questions where the answer is a list of numbers or an interval. Enter the first three numbers of the form ² where is a positive integer, as a commna separated list. You could have entered your answer as "1. 4.9" (without the quotes), or as "1, 1, 9", or as "2^2, 1^2, 3^2". The order of the numbers does not matter, and you can still let Edfinity evaluate expressions for you. Now we will enter a few intervals from the real line. Edfinity can handle standard interval notation. Let's start with real numbers satisfying 2<2<5. The usual interval nocation for this is [2,5). Enter it just as shown: With intervals, there is a difference between square brackets [] (which mean to include the end point) and parentheses () (which mean to not include the end point), and you will need to get them right to have the interval correct. If we want to enter an interval where one side is unbounded, such as the real numbers greater than 3, we would normally write (3,00). Since computer keyboards do not come with an infinity symbol, we just write out the word infinity. So, enter (3, infinity). If we had wanted -00, we would type-infinity instead Tinally, sometimes intervals come in more than one piece. For example, the inequality ¹2 25 is satisfied with 2 25 and also when 2-5. This would be normally written as the union of two intervals: (-∞, -5]U[5,00) To type this into Edfinity, we just use a capital U for the union symbol: (-infinity, -5] U [5, infinity) When using unions of intervals, the order of the smaller intervals does not matter, so you could also enter [5, infinity) U (-infiniry, -5].
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