Ho: μ = 17 kg H :μ > 17 kg Level of significance: a = 0.01 Sample size: n = 36 Test statistic: t = 2.290 Unknown populat

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hi, can u help me to answer this one? thank you.
Ho: μ = 17 kg H :μ > 17 kg Level of significance: a = 0.01 Sample size: n = 36 Test statistic: t = 2.290 Unknown population standard deviation T-Distribution Table a. Determine the critical value(s) for the proposed hypothesis test. + Round to three decimal places if necessary b. Conclude whether to reject the null hypothesis or not based on the test statistic. Reject Fail to Reject
Test the claim that the average weight of a new SUV is 1,940 kg, if a sample of 313 vehicle weights results in a sample mean of 1,932 kg, with a standard deviation of 62.8 kg. Use a 20% level of significance. Standard Normal Distribution Table a. Calculate the test statistic. 0.00 E Round to two decimal places if necessary 2 = b. Determine the critical value(s) for the hypothesis test. Round to two decimal places if necessary c. Conclude whether to reject the null hypothesis or not based on the test statistic. O Reject O Fail to Reject
Question 3 of 6 Determine if the conditions required for the normal approximation to the binomial are met. If so, calculate the test statistic, determine the critical value(s), and use that to decide whether there is sufficient evidence to reject the null hypothesis or not at the given level of significance. Standard Normal Distribution Table a. Calculate the test statistic. Z = 0.00 Ho: p = 0.139 H₁ p < 0.139 x=8 n = 77 a = 0.01 Round to two decimal places if necessary Enter 0 if normal approximation to the binomial cannot be used
a. Calculate the test statistic. Question 3 of 6 2 = 0.00 E Round to two decimal places if necessary Enter 0 if normal approximation to the binomial cannot be used b. Determine the critical value(s) for the hypothesis test. Round to two decimal places if necessary Enter 0 if normal approximation to the binomial cannot be used c. Conclude whether to reject the null hypothesis or not based on the test statistic. O Reject O Fail to Reject Cannot Use Normal Approximation to Binomial