zle 7. 8. 9. 10. 11. 12. 13. SSTR = 6,750 SSE= 8,000 nT=20 The test statistic to test the null hypothesis equals Ⓒa. 4.2

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answerhappygod
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zle 7. 8. 9. 10. 11. 12. 13. SSTR = 6,750 SSE= 8,000 nT=20 The test statistic to test the null hypothesis equals Ⓒa. 4.2

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Zle 7 8 9 10 11 12 13 Sstr 6 750 Sse 8 000 Nt 20 The Test Statistic To Test The Null Hypothesis Equals A 4 2 1
Zle 7 8 9 10 11 12 13 Sstr 6 750 Sse 8 000 Nt 20 The Test Statistic To Test The Null Hypothesis Equals A 4 2 1 (13.01 KiB) Viewed 28 times
Zle 7 8 9 10 11 12 13 Sstr 6 750 Sse 8 000 Nt 20 The Test Statistic To Test The Null Hypothesis Equals A 4 2 2
Zle 7 8 9 10 11 12 13 Sstr 6 750 Sse 8 000 Nt 20 The Test Statistic To Test The Null Hypothesis Equals A 4 2 2 (11.51 KiB) Viewed 28 times
Zle 7 8 9 10 11 12 13 Sstr 6 750 Sse 8 000 Nt 20 The Test Statistic To Test The Null Hypothesis Equals A 4 2 3
Zle 7 8 9 10 11 12 13 Sstr 6 750 Sse 8 000 Nt 20 The Test Statistic To Test The Null Hypothesis Equals A 4 2 3 (14.14 KiB) Viewed 28 times
zle 7. 8. 9. 10. 11. 12. 13. SSTR = 6,750 SSE= 8,000 nT=20 The test statistic to test the null hypothesis equals Ⓒa. 4.22 b. .84 Ho: H1 H2 H3=U4 Ha: At least one mean is different C..22 d. 45
8. 9. 10. 11. 12. 13. 14. O SSTR=6,750 SSE= 8,000 nr 20 Ho: P1=2= μ3= μ4 Ha: At least one mean is different The null hypothesis is to be tested at the 5% level of significance. The critical value from the table is, a. 4.08 b.3.24 c. 2.87 d. 8.7 OO
13. 14. 15. 16. 17. 18. 19. 20 21. . To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the three treatments. You are given the results below. . Treatment A B C 20 22 40 €99.39 d. 8.02 Observation 30 26 30 25 20 28 33 28 22 The null hypothesis is to be tested at the 1% level of significance. The critical value from the table is a. 4.26 Ob 16.69
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