Given That The Acceleration Vector Is A T 4 Cos 2t I 4 Sin 2t J 2t K The Initial Velocity Is V 0 I K And 1 (12.13 KiB) Viewed 37 times
Given That The Acceleration Vector Is A T 4 Cos 2t I 4 Sin 2t J 2t K The Initial Velocity Is V 0 I K And 2 (12.38 KiB) Viewed 37 times
Given that the acceleration vector is a(t)=(-4 cos(2t))i + (-4 sin(2t))j + (2t)k, the initial velocity is v(0)=i+k, and the initial position vector is r(0) i+j+k, compute: A. The velocity vector v(t) B. The position vector r(t) = i+ j+ i+ j+
Find the velocity and position vectors of a particle with acceleration a(t) = 4k, and initial conditions v(0) = 4j-2k and r(0) = li +4j+2k. v(t) 0 + 4e + 2² k = r(t)-11++
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