1. At time t = 0, a particle is ejected from the surface x² + 2y² + 32²=6 at the point (1, 1, 1) in a direction normal t

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1 At Time T 0 A Particle Is Ejected From The Surface X 2y 32 6 At The Point 1 1 1 In A Direction Normal T 1 (19.45 KiB) Viewed 26 times

1. At time t = 0, a particle is ejected from the surface x² + 2y² + 32²=6 at the point (1, 1, 1) in a direction normal to the surface at a (constant) speed of 15 units per second. At what time does it cross the sphere x² + y² +2²= 200? I will be checking your set up; use technology to approximate the solution. I think some programs can even give you the exact value answer.