1) find dy, 13 x² + 4 x ³9 13x²+4 x ³²² y + y² = 18 dx dx now find the equation of the tangent line to the curve ad (1,

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answerhappygod
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1) find dy, 13 x² + 4 x ³9 13x²+4 x ³²² y + y² = 18 dx dx now find the equation of the tangent line to the curve ad (1,

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1 Find Dy 13 X 4 X 9 13x 4 X Y Y 18 Dx Dx Now Find The Equation Of The Tangent Line To The Curve Ad 1 1
1 Find Dy 13 X 4 X 9 13x 4 X Y Y 18 Dx Dx Now Find The Equation Of The Tangent Line To The Curve Ad 1 1 (40.44 KiB) Viewed 20 times
1 Find Dy 13 X 4 X 9 13x 4 X Y Y 18 Dx Dx Now Find The Equation Of The Tangent Line To The Curve Ad 1 2
1 Find Dy 13 X 4 X 9 13x 4 X Y Y 18 Dx Dx Now Find The Equation Of The Tangent Line To The Curve Ad 1 2 (39.3 KiB) Viewed 20 times
1) find dy, 13 x² + 4 x ³9 13x²+4 x ³²² y + y² = 18 dx dx now find the equation of the tangent line to the curve ad (1, 1), in "mx+b" format. y = - find the equation of the tangent line to the curve (a lemniscate) 2 (x² + y²) ²= 25(x²-y²³) at the point (-3,1). The equation of this tangent line can be written in the form y=mx+b, where" m' is and where bis find the slope of the fangent line to the curve "-1x² + 4xy + 1y³ = 8" at the point (-4,-2).

2) / find_dy, - 8x² + 3x³y + y² = -4", 9 40 now find the equation dy of the tangent line to the curve at (1,1). write answer in "mx+b" format, y=. : ✓so Suppose that x+y=82, find dy: dx and find the equation of the tangent line at the point (x, y) = (-3,-1), y= find the slope of the tangent line to the curve-4x²-3xy-4y²³² = -136" at the point (-4,3). vor fand the offocyou of the palay Love sive 9k g
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