A college student works for hours without a break, assembling mechanical components. The cumulative number of components

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A college student works for hours without a break, assembling mechanical components. The cumulative number of components

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A College Student Works For Hours Without A Break Assembling Mechanical Components The Cumulative Number Of Components 1
A College Student Works For Hours Without A Break Assembling Mechanical Components The Cumulative Number Of Components 1 (19.54 KiB) Viewed 36 times
A College Student Works For Hours Without A Break Assembling Mechanical Components The Cumulative Number Of Components 2
A College Student Works For Hours Without A Break Assembling Mechanical Components The Cumulative Number Of Components 2 (26.6 KiB) Viewed 36 times
A college student works for hours without a break, assembling mechanical components. The cumulative number of components she has assembled after & hours can be modeled as 64 (h) = 111.35e-4545 components. (Note: Use technology to complete the question.) (a) When was the number of components assembled by the student increasing most rapidly? (Round your answer to three decimal places.) hours (b) How many components were assembled at that time? (Round your answer to one decimal place.) components What was the rate of change of assembly at that time? (Round your answer to three decimal places) components per hour (c) How might the employer use the information in part (a) to increase the student's productivity? The student's employer may wish to enforce a break after the calculated amount of time to prevent a decline in productivity. The student may only work certain days of the week to make sure productivity stays high The student's employer may have the student rotate to a different job before the calculated amount of time. The student's employer may set a higher quota for the calculated amount of time.

A college student works for 8 hours without a break, assembling mechanical components. The cumulative number of components she has assembled after h h 64 q(h) = 1+11.55-0.6545 components. (Note: Use technology to complete the question.) (a) When was the number of components assembled by the student increasing most rapidly? (Round your answer to three decimal places.) hours (b) How many components were assembled at that time? (Round your answer to one decimal place.) components What was the rate of change of assembly at that time? (Round your answer to three decimal places.) components per hour. (c) How might the employer use the information in part (a) to increase the student's productivity? O The student's employer may wish to enforce a break after the calculated amount of time to prevent a decline in productivity. The student may only work certain days of the week to make sure producti stays high. O The student's employer may have the student rotate to a different job before the calculated amount of time. The student's employer may set a higher quota for the calculated amount of time.
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