48. Find the value of t in the interval [0, 2n) that satisfies the given equation. csct= -2, cott > 0 8 8 a. b. C. ㅠ 6 5

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How do we get [0, pi/2] and pi/6 also why does csct=-2become csct= 2, is is because we do csc-1?
is there a different process for solving these questoin based onif they are sin, cos, tan, sec, csc, or cot?
48. Find the value of t in the interval [0, 2n) that satisfies the given equation. csct= -2, cott > 0 8 8 a. b. C. ㅠ 6 5T 6 d. No Solution a. 7T 6 O b. 49. Find the value of t in the interval [0, 2n) that satisfies the given equation. cott = √3, csct < 0 ㅠ 6 5T X Topic covered in 7.5 Report a problem 7T 6 d. No Solution Topic covered in 7.5 Report a problem

solution see. Now csc (t) = -2 t lies on csc (N = 2 Lies * = csc²¹(2) = 4 om Foor reference. t :: t = 1+2 3rd quadrant = 1+1 G cot (t) >0 ૩′ લખae) 0 = 771 For [0, 1] correct option (C) Ams