For H₂(g) + Br₂(g) ⇒ 2 HBr(g), K = 7.2 × 10-4 at 1362 K and AH is positive. A vessel is charged with 50.6 Pa HBr, 1390 P

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

For H₂(g) + Br₂(g) ⇒ 2 HBr(g), K = 7.2 × 10-4 at 1362 K and AH is positive. A vessel is charged with 50.6 Pa HBr, 1390 P

Post by answerhappygod »

For H G Br G 2 Hbr G K 7 2 10 4 At 1362 K And Ah Is Positive A Vessel Is Charged With 50 6 Pa Hbr 1390 P 1
For H G Br G 2 Hbr G K 7 2 10 4 At 1362 K And Ah Is Positive A Vessel Is Charged With 50 6 Pa Hbr 1390 P 1 (52.53 KiB) Viewed 43 times
For H G Br G 2 Hbr G K 7 2 10 4 At 1362 K And Ah Is Positive A Vessel Is Charged With 50 6 Pa Hbr 1390 P 2
For H G Br G 2 Hbr G K 7 2 10 4 At 1362 K And Ah Is Positive A Vessel Is Charged With 50 6 Pa Hbr 1390 P 2 (43.36 KiB) Viewed 43 times
For H₂(g) + Br₂(g) ⇒ 2 HBr(g), K = 7.2 × 10-4 at 1362 K and AH is positive. A vessel is charged with 50.6 Pa HBr, 1390 Pa H₂, and 3365 Pa Br₂ at 1362 K. Will the reaction proceed to the left or right to reach equilibrium? Calculate the pressure (in pascals) of each species at equilibrium. PH₂ right left = PBT ₂ = PHBr = If the mixture is compressed to half of its original volume, will the reaction proceed to the left or the right to Pa Pa Pa
ΓΗ, PBT₂ = PHBr = If the mixture is compressed to half of its original volume, will the reaction proceed to the left or the right to reestablish equilibrium? left neither right If the mixture is heated from 1362 to 1450 K, will HBr be formed or consumed to reestablish equilibrium? consumed neither O formed I a Pa Pa
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply