1.) Based on the following reaction: Glucose + Phosphate <—> Glucose-6-Phosphate + H2O as well as the additional info be

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1.) Based on the following reaction: Glucose + Phosphate<—> Glucose-6-Phosphate + H2O as well as the additional infobelow, calculate the equilibrium constant K’eq. Show yourcalculations and make sure to indicate the correct unit forK’eq.Reaction at 37°CT (K) = T (°C) + 273R= 8.31 J.mol-1.K-1ΔG°’ = + 14 kJ.mol-1
2.) In liver cells the physiological concentrations of thereactants are the following:[Glucose] = 5 mmol.L-1[Phosphate] = 5 mmol.L-1[G-6-P] = 0.25 mmol.L-1Calculate the change of free energy (ΔG) if the reaction takesplace at 37°C. Show your calculations. ExpressΔG in kJ.mol-1.