(8%) Problem 3: A circular loop of radius R = 11 cm is centered at the origin where there is a constant electric field E

Post by **answerhappygod** » Sun Jul 10, 2022 12:11 pm

: 8 Problem 3 A Circular Loop Of Radius R 11 Cm Is Centered At The Origin Where There Is A Constant Electric Field E 1 (10.68 KiB) Viewed 55 times

: 8 Problem 3 A Circular Loop Of Radius R 11 Cm Is Centered At The Origin Where There Is A Constant Electric Field E 2 (11.33 KiB) Viewed 55 times

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: 8 Problem 3 A Circular Loop Of Radius R 11 Cm Is Centered At The Origin Where There Is A Constant Electric Field E 4 (12.14 KiB) Viewed 55 times

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: 8 Problem 3 A Circular Loop Of Radius R 11 Cm Is Centered At The Origin Where There Is A Constant Electric Field E 6 (8.27 KiB) Viewed 55 times

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: 8 Problem 3 A Circular Loop Of Radius R 11 Cm Is Centered At The Origin Where There Is A Constant Electric Field E 8 (7.04 KiB) Viewed 55 times

: 8 Problem 3 A Circular Loop Of Radius R 11 Cm Is Centered At The Origin Where There Is A Constant Electric Field E 9 (13.34 KiB) Viewed 55 times

(8%) Problem 3: A circular loop of radius R = 11 cm is centered at the origin where there is a constant electric field E = Exi+ Eyj. For this problem assume Ex= II N/C and Ey = 119 N/C.
33% Part (b) What is the flux through the loop, in Nm²/C, when the loop is oriented so that its normal tor is in the negative y-direction? 0₂-0.45 Grade Summary Deductions Potential 94
(8%) Problem 4: It is found that there is a net electric flux of 3.7 x 104 Nm²/C inward through a spherical surface of radius 5.2 cm. -

50% Part (b) Where might additional electric charge lie with respect to the spherical surface? Inside the surface, but far from the calculated charge. Feedback: is available. * Attempts Remain All content © 2022 Expert TA, LLC
(8%) Problem 7: Suppose a 11 cm diameter conducting sphere, surrounded by air, has 1.3 C of excess charge on it.
33% Part (a) Calculate the electric field strength near the surface of the sphere, in newtons per coulomb. Grade Summary E-3.8712 sin() cotan() cos() asin() tan() acos() HE 7 4 8 5 9 6 HOME Deductions Potential 97% Submissions. Attempts remaining: (3% per attempt)
%) Problem 8: Suppose you have an electric field between two parallel conducting plates separated by 1.4 cm and having a potential difference (volta; tween them of 1.4 x 10* V.