A ball is thrown from the ground with an initial speed v0 = 42 m/sec at an angle 8 = 60° above the horizontal. 5.5 sec l

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A ball is thrown from the ground with an initial speed v0 = 42 m/sec at an angle 8 = 60° above the horizontal. 5.5 sec l

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A Ball Is Thrown From The Ground With An Initial Speed V0 42 M Sec At An Angle 8 60 Above The Horizontal 5 5 Sec L 1
A Ball Is Thrown From The Ground With An Initial Speed V0 42 M Sec At An Angle 8 60 Above The Horizontal 5 5 Sec L 1 (44.02 KiB) Viewed 47 times
A ball is thrown from the ground with an initial speed v0 = 42 m/sec at an angle 8 = 60° above the horizontal. 5.5 sec later, the ball hits point P. Point P is a horizontal distance L and a vertical distance h from where the ball was initially thrown. a) What is L? Answer: 115.5 m b) What is h? Answer: 51.8 m c) What is the speed of the ball just before it hits point P? Answer: 27.3 m/sec d) What is h max, the largest height the ball reaches above the ground.? Answer: 67.5 m. vo t = 0 sec/0 hmax 9 t = 5.5 sec h
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