A train is moving East with a constant speed of VT = 40 kph. Meanwhile, a man walks in the west direction on top of the

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A Train Is Moving East With A Constant Speed Of Vt 40 Kph Meanwhile A Man Walks In The West Direction On Top Of The 1 (42.75 KiB) Viewed 49 times

A train is moving East with a constant speed of VT = 40 kph. Meanwhile, a man walks in the west direction on top of the train at speed of VMT= 10 kph relative to the train. He accelerates uniformly at a rate of am = 5 m/s². At this same instant, Car C starts to round a curve at A with an initial speed of (Vc) A = 60 kph. After t = 2.EFG s, the car reaches point B of the curve where it has uniformly reduced its speed to (Vc)B= 50 kph. Determine the velocity (in kph) and acceleration (in m/s²) of the man relative to the car at t = 2.EFG s. -VM/T 10kph am 5m/s² t=0 (Vc)A= 60kph 100 m V+= 40kph t= 2.582 s (Vc)B= 50kph