- Problem 2 A Crate Weighing 400 Lb Is Suspended By Three Cables As Shown Allow The Following Geometry 4 4 Ft 1 4 1 (130.78 KiB) Viewed 37 times
Problem 2: A crate weighing 400 lb is suspended by three cables as shown. Allow the following geometry: 4 = 4 ft 1₂ = 4
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Problem 2: A crate weighing 400 lb is suspended by three cables as shown. Allow the following geometry: 4 = 4 ft 1₂ = 4
Problem 2: A crate weighing 400 lb is suspended by three cables as shown. Allow the following geometry: 4 = 4 ft 1₂ = 4 ft 1₂ = 6 ft W₂ = 2 ft W₂ = 4 ft D a) Express the weight of the crate in Cartesian vector form. b) Express cable AB as a unit vector. d) c) Express cable AC as a unit vector. Express cable AD as a unit vector. e) Determine the tension in cable AB. f) Determine the tension in cable AC. g) Determine the tension in cable AD. h) If the maximum force that cable AD can support is 850 lb, what is the largest weight crate that this system can support? i) When cable AD is at its maximum tension of 850 lb, what is the tension in cable AB when this occurs? j) When cable AD is at its maximum tension of 850 lb, what is the tension in cable AC when this occurs? T h₂ W₂ h₁ = 4 ft h₂ = 2 ft A W₁ 1 h₂