6. (a) An electric field intensity vector is given by E = 100 cos (cot-Bz) T, + 50 sin (cot+Bz)T, Where w and ß are cons

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6 A An Electric Field Intensity Vector Is Given By E 100 Cos Cot Bz T 50 Sin Cot Bz T Where W And Ss Are Cons 1 (116.17 KiB) Viewed 42 times

6 A An Electric Field Intensity Vector Is Given By E 100 Cos Cot Bz T 50 Sin Cot Bz T Where W And Ss Are Cons 2 (124.67 KiB) Viewed 42 times

6. (a) An electric field intensity vector is given by E = 100 cos (cot-Bz) T, + 50 sin (cot+Bz)T, Where w and ß are constants. Find the associated magnetic flux density vector B and the Poynting vector P=ExB 20 Two parallel conducting plates occupying the planes x = 0 and x = d are kept at potentials V = 0 and V = V, respectively. The medium between the plates is a perfect dielectric of non-uniform permittivity given by ε = E₁ + (E₂₁ - €. ) -— (⑥2 where &, and e, are constants. Find the solutions for the potential and the electric field intensity between the plates. 15
A thyristor circuit has an input voltage of 300 V and a load registance of 10 ohms. The circuit inductance is negligible. The operating frequency is 2 KHz. The required is 100V/us and discharge current is to be limited to 100A. Find (i) Values of R and C of the Snubber circuit. (ii) Power loss in the Snubber circuit. (ii) Power rating of the registor R of the Snubber circuit. 20