A solid lies between two planes perpendicular to the x-axis at x = 0 and x = 48. The cross-sections by planes perpendicu

[answerhappygod]

A Solid Lies Between Two Planes Perpendicular To The X Axis At X 0 And X 48 The Cross Sections By Planes Perpendicu 1 (48.37 KiB) Viewed 62 times

A solid lies between two planes perpendicular to the x-axis at x = 0 and x = 48. The cross-sections by planes perpendicular to the X x-axis are circular disks whose diameters run from the line y = 24 to the line y = x as shown in the accompanying figure. Explain why the solid has the same volume as a right circular cone with base radius 23 and height 48. y=x The height of it is y=34 48x The radius of a circular cross section of the solid at any value of x is The height of the solid is Locate the right circular cone with base radius 23 and height 48 so that its vertex is at the origin and its height is along the x-axis. This cone is the surface of revolution of the function about the x-axis. (Type an equation.) The radius of the cross-section of this right circular cone at any value of x is Apply Cavalieri's principle to state the conclusion. Choose the correct answer below. O A. Since the radii of the cross-sections of the solids are equal, the cross-sectional areas are equal. Since the solids have equal cross-sectional areas and equal heights, the solids have the same volume by Cavalieri's principle. O B. Since the base radii of the solids are equal, the base areas are equal. Since the base areas and the heights of the solids are equal, the solids have the same volume by Cavalieri's principle. O C. Since the radii of the cross-sections of the solids are equal, the cross-sectional areas are equal. Since the solids have equal cross-sectional areas, the solids have the same volume by Cavalieri's principle. O D. Since the base radii of the solids are equal, the areas of the bases are equal. The solids therefore have the same volume by Cavalieri's principle.