- A Random Sample Of 40 Adults With No Children Under The Age Of 18 Years Results In A Mean Daily Leisure Time Of 5 55 Hou 1 (20.54 KiB) Viewed 76 times
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.55 hou
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A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.55 hou
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.55 hours, with a standard deviation of 2.33 hours. A random sample of 40 adults with children under the age of 18 daily leisure time of 4.12 hours, with a standard deviation of 1.89 hours. Construct and interpret a 95% confidence interval for the mean difference in leisure time between adults with no children and adults within (2) La represent the mean leisure hours of adults with no children under the age of 18 and py represent the mean lesure hours of adults with children under the age of 18 The 95% confidence interval for (4-2) is the range from hours to hours (Round to two decimal places as needed) What is the interpretation of this confidence interval? OA. There is a 95% probability that the difference of the means is in the interval Conclude that there is a significant difference in the number of leisure hours. OB. There is a 95% probability that the difference of the means is in the interval Conclude that there is insufficient evidence of a significant difference in the number of leisure hours OC. There is 95% confidence that the difference of the means is in the interval. Conclude that there is insufficient evidence of a significant difference in the number of leisure hours. OD. There is 95% confidence that the difference of the means is in the interval. Conclude that there is a significant difference in the number of leisure hours