Assume that a procedure yields a binomial distribution with n=3 trials and a probability of success of p=0.80. Use a bin

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Assume That A Procedure Yields A Binomial Distribution With N 3 Trials And A Probability Of Success Of P 0 80 Use A Bin 1 (82.71 KiB) Viewed 78 times

Assume that a procedure yields a binomial distribution with n=3 trials and a probability of success of p=0.80. Use a binomial probability table to find the probability that the number of successes x is exactly 2. Click on the icon to view the binomial probabilities table. P(2)= (Round to three decimal places as needed.) Binomial Probabilities Table D 2 X 0 1 0 1 2 115 .10 42 60 30 20 320 30 980 902 810 848 490 360 250 160 000 000 000 002 2005 321 480 5:00 220 180 +062 810 348 160 250 540 312 302 350 370 387 320 312 216 20500108. 000 343 это 125 430 260 400 264 027 298 432 441 216 343 .125 441 Dar +767827 766 389 0- 1 384 243 136 8292 512 729 167 027 878 000 002 +0+1+04 078 I+ 0961 015 656 211 280 171 382 411 2 201 214 345 154 360- 834 325 265 412 0+ 0961 774 590 329 168078081 210 002 1 045 204 220 418 260 259 156 877 008 0+0+06 006 +0+#+1 H+ 2001 721 876 25 300 346 212 200 132 061 006 2001 2 3+1 800 761 122 230 212 346 309 205 073 1021 01 3 +0+0+ 366 025 077 158 259 260 410 225 2018 4 58+0+0+0+ 002 010 021 078 160 225 500 776 351 5 341 735 531 262 118 047 018 004 001 0++ ++ 0 257 222 254 251 205 187 004237 010 202 +0+ HI 1 201 JORT 248 234 138 060 don OF 2 3 +62 815 182 185 276 212 276 185 182 015 02 ++ 3 +381 315 080 138 338 311 224 246 068 201801 4 010 157 300 393 5 0- 68+0+0+0+ 001 004 0332568 A76 21806228 1066 257 372 367 247 13 902 341 124 275 246 26 4 0 Binomial Probabates 1 HI 0+ 268 FX P 275 125 Print 130 062026 412 346 350 255 316 375 316 076 154 250 346 150 930 Done POO 59 +0 0 1 2 0+ 154 043 2014 2012 410 22 371 335 3 410 961 3 DAT 016 247 118 262 531 225 341 6 000 002 0+0+0+0+0+. 085 217 004 00 364 877 025 2004 + 1+ 1 1 2 - X