Find a parametrization of the surface. The portion of the sphere x² + y² +2²=2 between the planes z = - √2 2 sps What is

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answerhappygod
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Find a parametrization of the surface. The portion of the sphere x² + y² +2²=2 between the planes z = - √2 2 sps What is

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Find A Parametrization Of The Surface The Portion Of The Sphere X Y 2 2 Between The Planes Z 2 2 Sps What Is 1
Find A Parametrization Of The Surface The Portion Of The Sphere X Y 2 2 Between The Planes Z 2 2 Sps What Is 1 (34.95 KiB) Viewed 70 times
part b
Find A Parametrization Of The Surface The Portion Of The Sphere X Y 2 2 Between The Planes Z 2 2 Sps What Is 2
Find A Parametrization Of The Surface The Portion Of The Sphere X Y 2 2 Between The Planes Z 2 2 Sps What Is 2 (17.53 KiB) Viewed 70 times
thank you:)
Find a parametrization of the surface. The portion of the sphere x² + y² +2²=2 between the planes z = - √2 2 sps What is the correct parameterization? Select the correct choice below and fill in the answer boxes within your choice. (Type exact answers.) OA. r(p.0)= i+ OB. r(,0)=j+ sps C. rp.8)=i+i+k. OD. r(,0)= i+ k, sos sas s0s s0s ses and z= s0s IN
Use the Green's Theorem area formula, shown below, to find the area of the region enclosed by the circle r(t) = (d cost+h)i + (dsint+k)j. 0sts 2x Area of R с - ydx The area of the circle is
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