A particle starts from the origin, moves along the X axis to (1, 0), then along the quarter of the circumferencex² + y²

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answerhappygod
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A particle starts from the origin, moves along the X axis to (1, 0), then along the quarter of the circumferencex² + y²

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A Particle Starts From The Origin Moves Along The X Axis To 1 0 Then Along The Quarter Of The Circumferencex Y 1
A Particle Starts From The Origin Moves Along The X Axis To 1 0 Then Along The Quarter Of The Circumferencex Y 1 (38.75 KiB) Viewed 50 times
A particle starts from the origin, moves along the X axis to (1, 0), then along the quarter of the circumferencex² + y² = 1, x ≥ 0, y ≥ 0 to the point (0,1) and then along the Y axis back to the origin. Find the work done on this particle by the force field F(x,y) = Senx, Seny + xy² + ) = (Senx, + 1 + ³) If c=75, find the value of W + c, where W is the work obtained. TU
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