- What Is The Equilibrium Constant For The Reaction At 298 K 2c S 3h G C H6 G Given A H 84 68 Kj A S 173 1 (36.82 KiB) Viewed 50 times
What is the equilibrium constant for the reaction at 298 K? 2C(s) + 3H₂(g) → C₂H6(g) Given: A,H° = -84.68 kJ; A,S°= -173
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What is the equilibrium constant for the reaction at 298 K? 2C(s) + 3H₂(g) → C₂H6(g) Given: A,H° = -84.68 kJ; A,S°= -173
What is the equilibrium constant for the reaction at 298 K? 2C(s) + 3H₂(g) → C₂H6(g) Given: A,H° = -84.68 kJ; A,S°= -173.8 J/K at 298 K. (R = 8.314 J/K-mol) a. 5.8 x 105 b. 1.0 × 10-5 c. e. 7.0 x 1014 8.6 x 10 10 d. 1.7 x 10-6