Please solve this problem, I want to make sure that my answers
are correct:
Please use the formula sheet provided
below
My answers:
a - R1 positive
b - R2 negative
c - R1 = 2*R2 ---> -R2 = R1/2 ---> R2 = - R1/ 2
>>>>>>>>>>>> R1 = 13.35 cm
d - f(new) = 6.5 cm
e- f(medium) = 28.93 cm
Problem 2 [20 points) For the parts of the below question, fill in the empty boxes with your answer (YOUR ANSWER MUST BE ONLY A NUMBER; DO NOT WRITE UNITS; DO NOT WRITE LETTERS). A thin biconvex lens made of heavy flint glass (n = 1.89) has a focal length in air of 5 cm. The radius of curvature of the first surface i twice the second surface's radius. C 0 C R2 the radius of the first surface? a) [3 points) What is the sign Choose one: Opositive Onegative b) [3 points) What is the sign of the radius of the second surface? Choose one: positive Onegative c) (5 points) Calculate the radius of curvature of the first surface Ri. R1 = ст d) (5 points) If R1 = 17.36 cm, R2 = 8.678 cm, n = 1.89, calculate the new focal length in air of this lens, fnew- fnew = Jcm e) (4 points) If the lens is now immersed in a medium that has an index of refraction of 1.575, calculate the focal length in the medium fmedium (use R1 = 17. 36 cm, R2 = 8.678 cm and n = 1.89). fmedium= ст
Chapter 5 = c= 3 108 m/s Mo = 12.56 x 10-7 T.m/A Eo = 8.85 x 10-12 C2/N.m2 h = 6.626 X 10-34 4 J. is = V W = = 2nf 217 = T 18 2 n = λ n k =* v= = 11 af f = Lenses += * = -1) (4 m) M = - => (^? 1 1 1 1 : nl Si - yi So Si f f nm R1 R2 So yo (Converging (Convex) lense:f > 0) (Diverging (Concave) lense: f < 0) Meaning Associated with the Signs of lens Parameters Quantity Sign + S. Real Object Virtual Object Si Real Image Virtual Image y. Erect Object Inverted Object Yi Erect Image Inverted Image M Erect Image Inverted Image f Convex lens Concave lens
Please solve this problem, I want to make sure that my answers are correct: Please use the formula sheet provided below
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