Titration of Vinegar with Sodium Hydroxide

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answerhappygod
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Titration of Vinegar with Sodium Hydroxide

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Titration of Vinegar with Sodium Hydroxide
ACTIVITY 1 continued 1. Calculate the volume of HCI solution. Volume = Mass / Density Volume = 10.00 g / 1.00 g/mL = 10.00 mL 2. Determine the moles of sodium hydroxide used to reach the end point. Moles of NaOH = 1.0 M x 6.2 mL x 1 L/ 1,000 mL = 0.0062 moles NaOH 3. Determine the moles of hydrochloric acid in the sample. Moles of NaOH = Moles of HCI at the equivalence point Moles of NaOH = 0.0062 moles Moles of HCI Calculated Percent Mass of Acetic Acid in Sampled Vinegar 4. Calculate the molarity of hydrochloric acid. 0.0062 moles/0.010 L = 0.62 M HCI Average Calculated Percent Mass of Acetic Acid in Sampled Vinegar 5. Calculate the mass of hydrochloric acid in the initial sample. Mass of HCI = Moles of HCI / Molar Mass of HCI Mass of HCI = 0.0062 mol x 36.46 g/mol = 0.23 g 6. Calculate the percent mass of hydrochloric acid in the initial sample. Percent Mass = (Mass of Solute / Total mass) x 100 Data Table 1: Titration of Vinegar with Sodium Hydroxide Name of Vinegar Sample Mass of Vinegar Volume of Vinegar Density = 1.005 g/mL Initial NaOH Volume in Syringe Final NaOH Volume in Syringe Volume of NaOH Delivered Moles of NaOH Delivered Moles of Acetic Acid in Sample Mass of Acetic Acid in Sample Calculated Molarity of Acetic Acid in the Sampled Vinegar Percent Mass = (Mass of HCI / Mass of solution) x 100 Percent Mass = (0.23 g/10.00 g) x 100 = 2.3 % Vinegar Sample 1 Vinegar Sample 2 Vinegar Sample 3
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