How many grams of Cl₂ are needed to form 84.1 g of AlCl3 ? 2 Al(s) + 3 Cl₂(g) → 2 AlCl3 (s) Step 1: Show the strategy fo

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How many grams of Cl₂ are needed to form 84.1 g of AlCl3 ? 2 Al(s) + 3 Cl₂(g) → 2 AlCl3 (s) Step 1: Show the strategy fo

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How Many Grams Of Cl Are Needed To Form 84 1 G Of Alcl3 2 Al S 3 Cl G 2 Alcl3 S Step 1 Show The Strategy Fo 1
How Many Grams Of Cl Are Needed To Form 84 1 G Of Alcl3 2 Al S 3 Cl G 2 Alcl3 S Step 1 Show The Strategy Fo 1 (179.93 KiB) Viewed 42 times
How Many Grams Of Cl Are Needed To Form 84 1 G Of Alcl3 2 Al S 3 Cl G 2 Alcl3 S Step 1 Show The Strategy Fo 2
How Many Grams Of Cl Are Needed To Form 84 1 G Of Alcl3 2 Al S 3 Cl G 2 Alcl3 S Step 1 Show The Strategy Fo 2 (208.76 KiB) Viewed 42 times
How many grams of Cl₂ are needed to form 84.1 g of AlCl3 ? 2 Al(s) + 3 Cl₂(g) → 2 AlCl3 (s) Step 1: Show the strategy for solving this problem. grams AlCl3 moles Al moles Cl₂ Answer Bank grams Al grams AlCl3 moles AlCl3 grams Cl₂ grams Cl₂
Step 2: Show the conversions required to solve this problem and calculate the grams of Cl₂. 84.1 g AlCl3 x grams of Cl₂: 26.98 g Al 1 mole Cl₂ Answer Bank 1 mole Al 1 mole AlCl3 2 moles Al 3 moles Cl₂ X 70.90 g Cl₂ 133.33 g AICI, 2 moles AIC13 = g Cl₂ g Cl₂
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