- Where Would A Second Mass Of 4 0 Kg Be Placed In Relation To The Pivot In Order To Balance The 5 0 M Board 3 0 Kg 1 0 1 (43.33 KiB) Viewed 44 times
Where would a second mass of 4.0 kg be placed in relation to the pivot, in order to balance the 5.0 m board. 3.0 kg 1 0.
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Where would a second mass of 4.0 kg be placed in relation to the pivot, in order to balance the 5.0 m board. 3.0 kg 1 0.
Where would a second mass of 4.0 kg be placed in relation to the pivot, in order to balance the 5.0 m board. 3.0 kg 1 0.75 m 3. Determine the length of the oard. 9.8 kg 3.0 kg -1.5m 0.75 m 1. a) -425 Nm b) 0.426 Nm c) 16 Nm 2) 1.3 m right 3) 3.75 m CS Scanned with CamScanner
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