Two point charges q₁ = +2.65nC and q2 = -6.25nC are 0.100 m apart. Point A is midway between them; point B is 0.080 m fr
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Two point charges q₁ = +2.65nC and q2 = -6.25nC are 0.100 m apart. Point A is midway between them; point B is 0.080 m fr
c. Find the work done by the electric field on a chargeof 2.50 nC that travels from point B topoint A.
Two point charges q₁ = +2.65nC and q2 = -6.25nC are 0.100 m apart. Point A is midway between them; point B is 0.080 m from 9₁ and 0.060 m from 92. (See (Figure 1).) Take the electric potential to be zero at infinity. Figure 91 -0.080 m B -0.060 m- -0.050 m→0.050 m- A 92 1 of 1