6 points How Did I Do? In an amusement park ride, a 65 kg person sits in a 140 kg cage, which in turn is attached to the

[answerhappygod]

6 Points How Did I Do In An Amusement Park Ride A 65 Kg Person Sits In A 140 Kg Cage Which In Turn Is Attached To The 1 (22.57 KiB) Viewed 50 times

6 points How Did I Do? In an amusement park ride, a 65 kg person sits in a 140 kg cage, which in turn is attached to the end of a bungee cord, and also anchored to the ground. The top of the bungee cord is then raised until it has stretched 9 meters. The anchor is released, and the cage (with the person inside) is propelled into the air. The bungee cord has a spring constant of 530 N/m.(a) How far above its anchored height will the cage and person go? h = Number Units (b) What is the maximum speed experienced by the rider on this ride? (Note: the equilibrium position of the system is not at the height where the bungee cord is completely unstretched.) Number Units Umax (c) What is the maximum acceleration experienced by the rider on this ride? amax Number Units (c) For safety reasons, the rider should not be subjected to accelerations greater than 1.8.g. What is the minimum mass required for the rider? mmin Number Units