In the figure (Figure 1), C1C1 = C5C5 = 8.6 μFμF and C2C2= C3C3= C4C4 = 4.3 μFμF . The applied potential is VabVab = 240 VV .
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Part A.) What is the equivalent capacitance of the networkbetweenpoints a and b? C= F This an
Part B.) Calculate the charge on each capacitor and thepotential difference across each capacitor. Q1 = C
Part C.) Express your answer using two significant figures. V1 =V
Part D.) Express your answer using two significant figures. Q2 =C
Part E.) Express your answer using two significant figures. V2 =V
Part F.) Express your answer using two significant figures. Q3 =C
Part G.) Express your answer using two significant figures. V3 =V
Part H.) Express your answer using two significant figures. Q4 =C
Part I.) Express your answer using two significant figures. V4 =V
Part J.) Express your answer using two significant figures. Q5 =C
Part K.) Express your answer using two significant figures. V5 =V
a b C₁ C5 C2 C3 CA
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