Torque (Nm) 0.008- 0.006- 0.004- 0.002- 10 Torque vs angular acceleration for single and double discs accelerated by a f

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answerhappygod
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Torque (Nm) 0.008- 0.006- 0.004- 0.002- 10 Torque vs angular acceleration for single and double discs accelerated by a f

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Torque Nm 0 008 0 006 0 004 0 002 10 Torque Vs Angular Acceleration For Single And Double Discs Accelerated By A F 1
Torque Nm 0 008 0 006 0 004 0 002 10 Torque Vs Angular Acceleration For Single And Double Discs Accelerated By A F 1 (127.36 KiB) Viewed 26 times
Torque Nm 0 008 0 006 0 004 0 002 10 Torque Vs Angular Acceleration For Single And Double Discs Accelerated By A F 2
Torque Nm 0 008 0 006 0 004 0 002 10 Torque Vs Angular Acceleration For Single And Double Discs Accelerated By A F 2 (85.96 KiB) Viewed 26 times
Torque (Nm) 0.008- 0.006- 0.004- 0.002- 10 Torque vs angular acceleration for single and double discs accelerated by a falling mass MA Linear Fit for: Double disc | Torque tau = mx+b m (Slope): 0.0002607 Nm/rad/s² b (Y-Intercept): 4.136E-005 Nm Correlation: 0.9999 RMSE: 3.030E-005 Nm 20 30 Angular Acceleration (rad/s²) Linear Fit for: Single disc | Torque tau = mx+b m (Slope): 0.0001598 Nm/rad/s² b (Y-Intercept): 9.711E-005 Nm Correlation: 0.9999 RMSE: 3.389E-005 Nm 40 ←
Question 5 (1 point) Consider the graph above that shows the torque as a function of angular acceleration for the single disc and double discs accelerated by a falling mass. From the linear regression of the plots, what is the value of the experimental moment of inertia (in g-m²) for only the second disc? Round your answer to 4 decimal places. Your Answer: Saved
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