Block 1, of mass m₁ = 3.50 kg, moves along a frictionless air track with speed v₁ - 25.0 m/s. It collides with block 2,

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answerhappygod
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Block 1, of mass m₁ = 3.50 kg, moves along a frictionless air track with speed v₁ - 25.0 m/s. It collides with block 2,

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Block 1 Of Mass M 3 50 Kg Moves Along A Frictionless Air Track With Speed V 25 0 M S It Collides With Block 2 1
Block 1 Of Mass M 3 50 Kg Moves Along A Frictionless Air Track With Speed V 25 0 M S It Collides With Block 2 1 (23.8 KiB) Viewed 44 times
Block 1 Of Mass M 3 50 Kg Moves Along A Frictionless Air Track With Speed V 25 0 M S It Collides With Block 2 2
Block 1 Of Mass M 3 50 Kg Moves Along A Frictionless Air Track With Speed V 25 0 M S It Collides With Block 2 2 (33.51 KiB) Viewed 44 times
Block 1, of mass m₁ = 3.50 kg, moves along a frictionless air track with speed v₁ - 25.0 m/s. It collides with block 2, of mass m₂ = 55.0 kg, which was initially at rest. The blocks stick together after the collision. (Eigure 1) Figure Before collision: m₁ After collision: m₂ 2 1 of 1 Part A Find the magnitude p, of the total initial momentum of the two-block system Express your answer numerically. ▸ View Available Hint(s) PR ΘΕΑΣΦΑ Submit Part B kg-m/s Find ty, the magnitude of the final velocity of the two-block system Express your answer numerically. View Available Hint(s) Review
Part C What is the change AK = Kfinal - Kinitial in the two-block system's kinetic energy due to the collision? Express your answer numerically in joules. ►View Available Hint(s) AK = Submit IVE ΑΣΦ C P ? J
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