An object stands on the common central axis of two thin, symmetric lenses. the object is placed 12.0 cm in front of the

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

An object stands on the common central axis of two thin, symmetric lenses. the object is placed 12.0 cm in front of the

Post by answerhappygod »

An object stands on the common central axis of two thin, symmetric lenses. the object is placed 12.0 cm in front of the first lens (converging lens) whose focal length is 8 cm. the second lens is a diverging lens whose focal length is also 8 cm. the distance between the lenses is 30 cm.a. Determine the characteristics of the final image by using thib-lens and magnification equations
An Object Stands On The Common Central Axis Of Two Thin Symmetric Lenses The Object Is Placed 12 0 Cm In Front Of The 1
An Object Stands On The Common Central Axis Of Two Thin Symmetric Lenses The Object Is Placed 12 0 Cm In Front Of The 1 (90.51 KiB) Viewed 43 times
b. Find the location if the final image by using ray diagrams (sketch the rays clearly)
Problem 3: (30 points) An object stands on the common central axis of two thin, symmetric lenses. The object is placed 12.0 cm in front of the first lens (converging lens) whose focal length is 8.0 cm. The second lens is a diverging lens whose focal length is also 8.0 cm. The distance between the lenses is 30.0 cm. a.) Determine the characteristics of the final image by using thin-lens and magnification equations. Give your reasoning. b.) Find the location of the final image by using ray diagrams (sketch the rays clearly). Object f₁ 12 cm 1st Lens f₁ 30 cm 2nd Lens f₂
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply