A computer has 16-bit virtual addresses and 4-KB pages.It has 32 KBphysical memory. A snap shot of the mapping from pages to pageframes is as follows.
A Computer Has 16 Bit Virtual Addresses And 4 Kb Pages It Has 32 Kb Physical Memory A Snap Shot Of The Mapping From Pa 1 (64.91 KiB) Viewed 33 times
Calculate the physical address for each of followingvirtual addresses:a) virtual address 21
b) virtual address 4097
c) virtual address 13002
d) virtual address 20003
Virtual address space 60K-64K X 56K-60K X 52K-56K X 48K-52K X 44K-48K 7 40K-44K X 36K-40K 5 32K-36K X 28K-32K X 24K-28K X 20K-24K 3 16K-20K 4 12K-16K 0 8K-12K 4K-8K OK-4K 061 2 Virtual page Physical memory address 28K-32K 24K-28K 20K-24K 16K-20K 12K-16K 8K-12K 4K-8K OK-4K
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!