Fun F D E G H The Abstract Syntax Tree Off Is The Following F D E G H D Apply H D E G G E 0 B 1 (25.79 KiB) Viewed 41 times
Fill in the blank, reducing all types to basic types and typeconstructors if possible: • Type of d = • Type of e = • Type of g =• Type of h = • Type that f returns =
fun f (d, e, g, h) The abstract syntax tree off is the following: / / f(d, e, g, h) d apply. = h[d(e, g)] + g[e[0]] + "bar" "bar" Fill in the blank, reducing all types to basic types and type constructors if possible: Type of d = Type of e Type of g Type of h Type that freturns-
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!