A B FA10 = 2010 mol/min/ CA10 = 1100 mol/min E PA=0/0 70 CA2 mol/ (Les) V= 110 m ²³ T = 100s 2KOH + H2504 125 kg +54L CA

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answerhappygod
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A B FA10 = 2010 mol/min/ CA10 = 1100 mol/min E PA=0/0 70 CA2 mol/ (Les) V= 110 m ²³ T = 100s 2KOH + H2504 125 kg +54L CA

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A B Fa10 2010 Mol Min Ca10 1100 Mol Min E Pa 0 0 70 Ca2 Mol Les V 110 M T 100s 2koh H2504 125 Kg 54l Ca 1
A B Fa10 2010 Mol Min Ca10 1100 Mol Min E Pa 0 0 70 Ca2 Mol Les V 110 M T 100s 2koh H2504 125 Kg 54l Ca 1 (104.64 KiB) Viewed 32 times
Production and preparation of potassium sulfateApproximately 1.5 million tons were produced in 1985, usually by reactionPotassium chloride with sulfuric acid, in a process similar to the Mannheim processMannheim for the production of sodium sulfate. The process includes creating an intermediarypotassium bisulfate, an exothermic reaction that occurs atroom temperature:KCI + H2SO4 → HCI + KHSO4The second step of the process is endothermic, and requires energy input:KCI + KHSO4 → HCI + K2SO4In the laboratory, it can be prepared through the reaction of either potassium hydroxideOr potassium carbonate with sulfuric acid.
A B FA10 = 2010 mol/min/ CA10 = 1100 mol/min E PA=0/0 70 CA2 mol/ (Les) V= 110 m ²³ T = 100s 2KOH + H2504 125 kg +54L CA=0, 13 mol/L CB=0188 mol/L. FA= 1+3 mol/min CA=0,23 mol/min FB= 8,8 mol/min CB=0188 Mol/L + K2504 + 2H₂0 -170 Kg
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