Create a Matlab script that solves the tape correction due to temperature. The input parameters are the Nominal and Meas

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Create a Matlab script that solves the tape correction due to temperature.
The input parameters are the Nominal and Measured Lengths, Standard and Field Temperatures, and the coefficient for linear expansion.
Outputs shall be
temperature correction per tape
temperature correction for whole measured length
Corrected Measured Length

Create A Matlab Script That Solves The Tape Correction Due To Temperature The Input Parameters Are The Nominal And Meas 1 (48.98 KiB) Viewed 45 times

Create A Matlab Script That Solves The Tape Correction Due To Temperature The Input Parameters Are The Nominal And Meas 2 (40.86 KiB) Viewed 45 times

Create A Matlab Script That Solves The Tape Correction Due To Temperature The Input Parameters Are The Nominal And Meas 3 (17.45 KiB) Viewed 45 times

Create A Matlab Script That Solves The Tape Correction Due To Temperature The Input Parameters Are The Nominal And Meas 4 (26.37 KiB) Viewed 45 times

Create A Matlab Script That Solves The Tape Correction Due To Temperature The Input Parameters Are The Nominal And Meas 5 (22.06 KiB) Viewed 45 times

VARIATIONS IN TEMPERATURE + the correction applied to the length of the tape due to change in temperature Ct is given by Ct = aL(T-To) Where: + α L + T + To is the coefficient of linear expansion or the amount of change in length per unit length per degree change in temperature; for a steel tape, a = 0.0000116/= 0.00000645/F is the length of the tape or length of line measured is the observed temperature of the tape at the time of measurement is the temperature at which the tape was standardized
CORRECTION DUE TO TEMPERATURE A steel tape with a coefficient of linear expansion of 0.0000116/°C is known to be 50 m long at 20°C. The tape was used to measure a line which was found to be 532.28 m long when the temperature was 35°C. Determine the following: + Temperature correction per tape length + Temperature correction for the measured length + Correct length of the line
+ Temperature correction per tape length α = 0.0000116/°C NL = 50 m @ T, = 20°C ML = 532.28 m @ T = 35°C - Ct = (0.0000116/°C)(50 m)(35°C – 20°C) = 0.00870 m (too long) ≈ 0.009 m (too long)
Temperature correction for the measured length α = 0.0000116/°C NL = 50 m @ T, = 20°C ML = 532.28 m @ T = 35°C c = 0.00870 m (too long) Ct = (0.0000116/°C) (532.28 m) (35°C -20°C) = 0.09262 m (too long) ≈ 0.093 m (too long) Ct = (0.00870) (532.28 m 50 m = 0.09262 m
+ Correct length of the line α = 0.0000116/°C NL = 50 m @ T, = 20°C ML = 532.28 m @ T = 35°C Ct = 0.00870 m (too long) 0.9262 m Ct CL = 532.28 m+ 0.09262 m = 532.37262 m ≈ 532.373 m CL = (532.28 m)(1+ n) (1. 0.00870 m 50 m = 532.37262 m