Simple Curves A Highway Curve Was Designed To Connect Intersecting Tangents At Pl Back Tangent N 30 25 E Forward T 1 (60.57 KiB) Viewed 25 times
Simple Curves A Highway Curve Was Designed To Connect Intersecting Tangents At Pl Back Tangent N 30 25 E Forward T 2 (42.41 KiB) Viewed 25 times
Simple Curves: A highway curve was designed to connect intersecting tangents at Pl. Back tangent = N 30° 25' E Forward tangent = S 69°35' E Degree of curve = 6⁰ Station PI = 2+222.22 8. Determine the length of tangent distance (PI to PT). a) 145.66m b) 123.56m 9. Compute the distance from the PI to the midpoint of the curve. a) 58.33m b) 35.67m c) 37.78m c) 160.26m 10. Determine the length of curve (PC to PT, arc length). a) 256.78m b) 234.78m c) 266.54m 11. Determine the stationing of PT. a) 2 + 244.56 b) 2 + 328.50 c) 2 + 289.89 d) 142.33m d) 25.56m d) 276.45m d) 2 + 301.34
Layout by coordinates method: Given are the coordinates of two points P1 and P2. It is required to layout point P2 from an instrument set up at Point P1. P1 P2 Northings (m) Eastings (m) 456.34 567.45 398.12 485.70 6. Determine the bearing to layout point P2. a) S 60°55' W b) N 60°36' W 7. Compute the distance to layout point P2. a) 140.45m b) 100.36m c) N 70°10' W c) 129.90m d) S 54°33' W d) 110.30m
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