- Given Information For The Column P1 599 Kn P2 139 8 Kn Cross Section 315x315 Mm E 18200 Mpa Lu 5 1 M K 1 0 I 1 (87.99 KiB) Viewed 39 times
Given Information for the column: P1 = 599 KN, P2 = 139.8 kN Cross Section 315x315 mm E = 18200 MPa Lu = 5.1 m k = 1.0 i
-
- Site Admin
- Posts: 899603
- Joined: Mon Aug 02, 2021 8:13 am
Given Information for the column: P1 = 599 KN, P2 = 139.8 kN Cross Section 315x315 mm E = 18200 MPa Lu = 5.1 m k = 1.0 i
Given Information for the column: P1 = 599 KN, P2 = 139.8 kN Cross Section 315x315 mm E = 18200 MPa Lu = 5.1 m k = 1.0 i) Find the primary moment on the column from lateral load. ii) Find the estimated total moment, including the secondary moment from lateral deflection, using the appropriate magnification factor. + 1 T Lu/3 2Lu/3 P1↓ L P1 t P2