A thin polymer plate PQR is deformed so that corner Q is displaced downward 0.9 mm to new position Q', as shown in. Dete

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

A thin polymer plate PQR is deformed so that corner Q is displaced downward 0.9 mm to new position Q', as shown in. Dete

Post by answerhappygod »

A Thin Polymer Plate Pqr Is Deformed So That Corner Q Is Displaced Downward 0 9 Mm To New Position Q As Shown In Dete 1
A Thin Polymer Plate Pqr Is Deformed So That Corner Q Is Displaced Downward 0 9 Mm To New Position Q As Shown In Dete 1 (173.43 KiB) Viewed 38 times
A thin polymer plate PQR is deformed so that corner Q is displaced downward 0.9 mm to new position Q', as shown in. Determine the shear strain at Q' associated with the two edges (PQ and QR). Assume a = 150 mm, b = 216 mm, c = 180 mm, and A = 0.9 mm. a b 가 P R C Q 10' Answer: Shear strain y = i A X prad.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Top
Post Reply

Return to “Archived Questions & Answers”