1 14 J 1 In(1 +49 Step 6 Combining these results and including the constant of integration, C, we finally have the follo

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1 14 J 1 In(1 +49 Step 6 Combining these results and including the constant of integration, C, we finally have the follo

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1 14 J 1 In 1 49 Step 6 Combining These Results And Including The Constant Of Integration C We Finally Have The Follo 1
1 14 J 1 In 1 49 Step 6 Combining These Results And Including The Constant Of Integration C We Finally Have The Follo 1 (223.2 KiB) Viewed 42 times
1 14 J 1 In(1 +49 Step 6 Combining these results and including the constant of integration, C, we finally have the following. 7t ·J. 1 + 49t² tarctan (71) — ½ln(497² +1) + Cx. arctan 7t dt = t arctan 7t = 49 t²). dt
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