A 69 Kg Skydiver Jumps Out Of An Airplane We Assume That The Forces Acting On The Body Are The Force Of Gravity And A R 1 (41.15 KiB) Viewed 53 times
A 69 kg skydiver jumps out of an airplane. We assume that the forces acting on the body are the force of gravity and a retarding force of air resistance with direction opposite to the direction of motion and with magnitude co² where c = 0.185 kg and v(t) is the velocity of the skydiver at time € (and upward is positive velocity). The gravitational constant is g = 9.8m/s². m a) Find a differential equation for the velocity v: dv dt b) Determine the terminal velocity in meters per second for free-fall (no parachute). terminal velocity = m/s Note: Answer should be negative for downward velocity.
A drug is administered intravenously at a constant rate of r mg/hour and is excreted at a rate proportional to the quantity present, with constant of proportionality k > 0. (a) Set up a differential equation for the quantity, Q, in milligrams, of the drug in the body at time t hours. Your answer will contain the unknown constants r and k. (b) Solve this differential equation, assuming there is no drug in the body initially. Your answer will contain r and k. Q (c) What is the limiting long-run value of Q? lim Q(t) = t→∞
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!