Question 15 II -10 III -5 10 5 -10 y-azis P(3,5) 5 (0,0) origin = -8cos 30° i + 8 sin 30°j = -8cos 30° i - 8 sin 30°j =

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Question 15 Ii 10 Iii 5 10 5 10 Y Azis P 3 5 5 0 0 Origin 8cos 30 I 8 Sin 30 J 8cos 30 I 8 Sin 30 J 1 (106.29 KiB) Viewed 57 times

Question 15 II -10 III -5 10 5 -10 y-azis P(3,5) 5 (0,0) origin = -8cos 30° i + 8 sin 30°j = -8cos 30° i - 8 sin 30°j = -8cos 30° - 8sin 30° = -8sin 30° i-8cos 30°j I = 8cos 30° i - 8 sin 30°j 10 IV z-aris Ax<0 III A₂ <0 Part 1 of 3: Vector B is 8 m at a -30° from the negative x-axis in Quadrant III. Vector B in component form is: 0 YA A 2.5 pts