A 1:175-N uniform boom at p = 64.0° to the vertical is supported by a cable at an angle 0 = 26.0° to the horizontal as s

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A 1:175-N uniform boom at p = 64.0° to the vertical is supported by a cable at an angle 0 = 26.0° to the horizontal as s

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A 1 175 N Uniform Boom At P 64 0 To The Vertical Is Supported By A Cable At An Angle 0 26 0 To The Horizontal As S 1
A 1 175 N Uniform Boom At P 64 0 To The Vertical Is Supported By A Cable At An Angle 0 26 0 To The Horizontal As S 1 (36.35 KiB) Viewed 63 times
A 1:175-N uniform boom at p = 64.0° to the vertical is supported by a cable at an angle 0 = 26.0° to the horizontal as shown in the figure below. The boom is pivoted at the bottom, and an object of weight m = 2 425 N hangs from its top. M (a) Find the tension in the support cable.. 1760.80 x Your response is off by a multiple of ten, kt (b) Find the components of the reaction force exerted by the floor on the boom. 2828.11 X magnitude Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. KN direction: horizontal component right 1582 6 X vertical component magnitude your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully, kt direction upward✔✔
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