A 12 0 N Object Is Oscillating In Simple Harmonic Motion At The End Of An Ideal Vertical Spring Its Vertical Position Y 1 (65.48 KiB) Viewed 62 times
A 12.0-N object is oscillating in simple harmonic motion at the end of an ideal vertical spring. Its vertical position y as a function of time t is given by y(t) = 4.50 cm cos [(19.5 s¯¹)t — π/8]. (a) What is the spring constant of the spring? ΠΙΑΣΦ Submit Part B Request Answer ? (b) What is the maximum acceleration of the object? —| ΑΣΦ ? N/m m/s²
(c) What is the maximum speed that the object reaches? VE ΑΣΦ Submit Part D Request Answer ? VG ΑΣΦ (d) How long does it take the object to go from its highest point to its lowest point? m/s ? S
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