A 1.9-MeV (kinetic energy) proton enters a 0.25-T field, in a plane perpendicular to the field.

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answerhappygod
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A 1.9-MeV (kinetic energy) proton enters a 0.25-T field, in a plane perpendicular to the field.

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A 1 9 Mev Kinetic Energy Proton Enters A 0 25 T Field In A Plane Perpendicular To The Field 1
A 1 9 Mev Kinetic Energy Proton Enters A 0 25 T Field In A Plane Perpendicular To The Field 1 (15.28 KiB) Viewed 64 times
Question: what is the radius of its path?
A 1.9-MeV (kinetic energy) proton enters a 0.25-T field, in a plane perpendicular to the field.
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